Ionic EquilibriumHard
Question
One mole of CH3COOH and one mole of C2H5OH reacts to produce 
mol of CH3COOC2H2. The equilibrium constant is:
mol of CH3COOC2H2. The equilibrium constant is:Options
A.2
B.+2
C.-4
D.+4
Solution
CH3COOH + C2H5OH → CH3COOC2H5 + H2O
At start 1 mole 1 mole 0 0
Atequb. 1 - 1 -
Let the total volume = V L
∴ [CH3OOH] =
V mol/L
[C2H5OH =V mol/L
[CH3COOC25] =
V mol/L
[H2O] =V mol/L
∴ K =
= 4
At start 1 mole 1 mole 0 0
Atequb. 1 -
1 - Let the total volume = V L
∴ [CH3OOH] =
V mol/L[C2H5OH =
V mol/L[CH3COOC25] =
V mol/L[H2O] =
V mol/L∴ K =
= 4Create a free account to view solution
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