Ionic EquilibriumEasy

Question

One mole of CH3COOH and one mole of C2H5OH reacts to produce mol of CH3COOC2H2. The equilibrium constant is:

Options

A.2
B.+2
C.-4
D.+4

Solution

CH3COOH + C2H5OH → CH3COOC2H5 + H2O
At start         1 mole         1 mole         0         0
Atequb.         1 -         1 -                
Let the total volume = V L
∴ [CH3OOH] = V mol/L
[C2H5OH = V mol/L

[CH3COOC25] = V mol/L
[H2O] = V mol/L
∴ K = = 4

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