Chemical EquilibriumHard

Question

Carbon monoxide in water gas reacts with steam according to the following reaction.

CO(g) + H2O(g) $\rightleftharpoons$CO2(g) + H2(g); Keq = 0.3333

If two volumes of water gas (containing 1:1 of CO and H2) are mixed with five volumes of steam, then the volume ratio of the four gases present at equilibrium is

Options

A.1: 1: 1: 1
B.1: 3: 1: 1
C.1: 15: 1: 5
D.1: 9: 1: 3

Solution

CO(g) + H2O(g) $\rightleftharpoons$CO2(g) + H2(g)

Initial 1 5 0 1

Equilibrium 1 – x 5 – x x 1 – x

Now, $K_{eq} = \frac{1}{3} = \frac{x.(1 + x)}{(1 - x)(5 - x)} \Rightarrow x = \frac{1}{2}$

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