Chemical EquilibriumHard
Question
When S in the form of S8 is heated at 900 K, the initial pressure of 1 atm falls by 30% at equilibrium. This is because of conversion of some S8(g) to S2(g). The value of KP for the reaction is
Options
A.0.011 atm–3
B.2.96 atm3
C.1.71 atm3
D.204.8 atm3
Solution
S8(g) $\rightleftharpoons$ 4S2(g)
Initial partial pressure 1 atm 0
Equ. partial pressure 1 – 0.3 4 × 0.3
= 0.7 atm = 1 .2 atm
$\therefore K_{p} = \frac{(1.2)^{4}}{0.7} = 2.96\text{ at}\text{m}^{3}$
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