Chemical EquilibriumHard
Question
The value of KP for the process: CuSO4·5H2O(s) $\rightleftharpoons$CuSO4·3H2O(s) + 2H2O(g) is 1.21 × 10–4 atm2 at certain temperature. If aqueous tension at that temperature is 40 torr, then at what relative humidity of air will CuSO4·5H2O effloresces?
Options
A.Above 40.8%
B.Below 40.8%
C.Above 20.9%
D.Below 20.9%
Solution
$Q_{P} < K_{P} \Rightarrow P_{H_{2}O}^{2} < K_{P}$
$\Rightarrow \left( \frac{40}{760} \times \frac{R.H.}{100} \right)^{2} < 1.21 \times 10^{- 4} $$$\therefore R.H. < 20.9\%$$
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