Chemical EquilibriumHard

Question

One mole of N2O4 (g) at 300 K is kept in a closed container under one atm. It is heated to 600 K when 20% by mass of N2O4(g) decomposes to NO2(g). The resultant pressure is

Options

A.1.2 atm
B.2.4 atm
C.2.0 atm
D.1.0 atm

Solution

N2O4 $\rightleftharpoons$ 2NO2

1 mole 0

Final 1 – 0.2 2 × 0.2

= 0.8 mole = 0.4 mole

Now, $\frac{P_{1}}{n_{1}T_{1}} = \frac{P_{2}}{n_{2}T_{2}} \Rightarrow \frac{1}{1 \times 300} = \frac{P_{2}}{1.2 \times 600}$

⇒ P2 = 2.4 atm

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