Chemical EquilibriumMedium
Question
One mole of N2O4 (g) at 300 K is kept in a closed container under one atm. It is heated to 600 K when 20% by mass of N2O4(g) decomposes to NO2(g). The resultant pressure is
Options
A.1.2 atm
B.2.4 atm
C.2.0 atm
D.1.0 atm
Solution
N2O4 $\rightleftharpoons$ 2NO2
1 mole 0
Final 1 – 0.2 2 × 0.2
= 0.8 mole = 0.4 mole
Now, $\frac{P_{1}}{n_{1}T_{1}} = \frac{P_{2}}{n_{2}T_{2}} \Rightarrow \frac{1}{1 \times 300} = \frac{P_{2}}{1.2 \times 600}$
⇒ P2 = 2.4 atm
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