Chemical EquilibriumMedium
Question
For the reaction A + B$\rightleftharpoons$C + D, the initial concentration of A and B is equal, but the equilibrium concentration of C is twice that of equilibrium concentration of A. The equilibrium constant is
Options
A.4
B.9
C.1/4
D.1/9
Solution
A + B $\rightleftharpoons$ C + D
Initial cM cM 0 0
Equilibrium (c – x)M (c - x)M x M x M
From question: $x = 2 \times (x - x) \Rightarrow x = \frac{2}{3}c$
$\therefore K = \frac{x.x}{(c - x)(c - x)} = 4$
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