Chemical EquilibriumHard

Question

The value of KP for the reaction N2O4(g) $\rightleftharpoons$2NO2 is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is

Options

A.$\frac{100}{\sqrt{2}}$
B.50
C.$\frac{50}{\sqrt{2}}$
D.$10\sqrt{2}$

Solution

$K_{p} = \frac{4\alpha^{2}.P}{1 - \alpha^{2}} \Rightarrow 640 = \frac{4\alpha^{2} \times 160}{1 - \alpha^{2}} \Rightarrow \alpha = \frac{1}{\sqrt{2}}$

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