Chemical EquilibriumMedium
Question
The value of KP for the reaction N2O4(g) $\rightleftharpoons$2NO2 is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is
Options
A.$\frac{100}{\sqrt{2}}$
B.50
C.$\frac{50}{\sqrt{2}}$
D.$10\sqrt{2}$
Solution
$K_{p} = \frac{4\alpha^{2}.P}{1 - \alpha^{2}} \Rightarrow 640 = \frac{4\alpha^{2} \times 160}{1 - \alpha^{2}} \Rightarrow \alpha = \frac{1}{\sqrt{2}}$
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
What can you say about the existance of A if the potential energy diagram for the reaction A → B looks like...What will the change on increasing the pressure at equilibrium water - water vapour?...Calculate equilibrium constant (approx) at 25oC for the cell reaction Fe(s) + CuSO4 ⇋ FeSO4 + Cu(s)Given : EoFe/Fe...For the reaction XY2(g) $\rightleftharpoons$XY(g) + Y(g), the reaction is started with initial pressure of XY2, 600 mm H...If the value of an equilibrium constant for a particular reaction is 1.6 × 1012, then at equilibrium the system wil...