Chemical EquilibriumMedium
Question
The equilibrium constant for the reaction 3C2H2 $\rightleftharpoons$C6H6 is 4.0 at T K. If the equilibrium concentration of C2H2 is 0.5 M, then the concentration of C6H6 at equilibrium is
Options
A.0.5 M
B.1.5 M
C.5 × 10−2 M
D.0.25 M
Solution
$K = \frac{\left\lbrack C_{2}H_{6} \right\rbrack}{\left\lbrack C_{2}H_{2} \right\rbrack^{3}} \Rightarrow 4 = \frac{\left\lbrack C_{2}H_{6} \right\rbrack}{(0.5)^{3}} \Rightarrow \left\lbrack C_{2}H_{6} \right\rbrack = 0.5\text{ M}$
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