Chemical EquilibriumMedium
Question
In a closed tube, HI(g) is heated at 440°C up to establishment of equilibrium. If it dissociates into H2(g) and I2(g) up to 22%, then the dissociation constant is
Options
A.0.282
B.0.0796
C.0.0199
D.1.99
Solution
2HI(g) $\rightleftharpoons$ H2(g) + I2(g)
Equilibrium $1 - \alpha$ $\frac{\alpha}{2}$ $\frac{\alpha}{2}$
= 0.78 = 0.11 = 0.11
$K = \frac{0.11 \times 0.11}{(0.78)^{2}} = 0.0199$
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