Redox and Equivalent ConceptMedium

Question

One gram of the acid C6H10O4 requires 0.768 g of KOH for complete neutralization. How many neutralizable hydrogen atoms are in this molecule?

Options

A.4
B.3
C.2
D.1

Solution

$n_{eq}C_{6}H_{10}O_{4} = n_{eq}KOH$

Or $\frac{1}{146} \times \text{basicity=}\frac{0.768}{56} \times 1 $$$\Rightarrow \text{Basicity of }C_{6}H_{10}O_{4} = 2$$

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