Aqueous HCl reacts with ${MnO}_{2}( ext{ }s)$ to form ${MnCl}_{2}(aq)$, ${Cl}_{2}( ext{ }g)$ and $

Question

Aqueous HCl reacts with ${MnO}_{2}(	ext{ }s)$ to form ${MnCl}_{2}(aq)$, ${Cl}_{2}(	ext{ }g)$ and $H_{2}O(l)$. What is the weight (in g ) of ${Cl}_{2}$ liberated when 8.7 g of ${MnO}_{2}(	ext{ }s)$ is reacted with excess aqueous HCl solution? (Given Molar mass in $g{mol}^{- 1}Mn = 55,Cl = 35.5,O = 16,H = 1$ )

Accepted Answer

${MnO}_{2} + 4HCl ightarrow {MnCl}_{2} + {Cl}_{2} + 2H_{2}O$$\frac{8.7}{87}\ $ Excess$= 0.1$ mole 0.1 moleWt. of ${Cl}_{2}$ obtained $= 0.1 	imes 71 = 7.1	ext{ }g$

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