Redox and Equivalent ConceptMedium
Question
A volume of 100 L of hard water requires 5.6 g of lime for removing temporary hardness. The temporary hardness in ppm of CaCO3 is
Options
A.56
B.100
C.200
D.112
Solution
Temporary hardness = $\left( \frac{\frac{5.6}{100} \times 1000}{56} \right) \times 200 = 100\text{ ppm}$
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