Redox and Equivalent ConceptHard
Question
An oxide of iron contains 30% oxygen by mass. The oxidation state of iron in this oxide is (Fe =56)
Options
A.+1
B.+2
C.+3
D.+4
Solution
$\frac{N_{Fe}}{N_{O}} = \frac{70/56}{30/16} = \frac{2}{3} \Rightarrow \text{Formula = F}\text{e}_{2}O_{3}$
∴ Oxidation state of Fe = +3.
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely...A quantity of 0.5 g of a metal nitrate gave 0.43 g of metal sulphate....Which of the following is not a disproportionation reaction ?...Equivalent weight of H2SO4 in the reaction Mg + 2H2SO4 → MgSO4 + SO2 + 2H2O, is...The oxidation number of K in KO2 is...