Redox and Equivalent ConceptHard
Question
To 1 L of 1.0 M impure H2SO4 sample, 1.0 M NaOH solution was added and a plot was obtained as follows:
The % purity of H2SO4 and the slope of curve, respectively, are;
Options
A.75% - 1/2
B.75% - 1
C.50% - 1/3
D.50% - 1/2
Solution
i. Moles of NaOH = 1.0 M × 1.5 L = 1.5 mol
Moles of H2SO4 = 1.0 M × 1L = 1.0 mol
2 NaOH + H2SO4 → Na2SO4 + 2H2O
2mol 1 mol
Moles of H2SO4 reacted with NaOH
=
mol of NaOH
=
× 1.5 = 0.75 mol H2SO4
%purity of H2SO4 =
= 75%
ii. For slope: = 1
Slope =
Moles of H2SO4 = 1.0 M × 1L = 1.0 mol
2 NaOH + H2SO4 → Na2SO4 + 2H2O
2mol 1 mol
Moles of H2SO4 reacted with NaOH
=
mol of NaOH=
× 1.5 = 0.75 mol H2SO4 %purity of H2SO4 =
= 75%ii. For slope: = 1
Slope =
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