The vapour density of a volatile chloride of a metal is 74.6. If the specific heat of the metal is 0

Question

The vapour density of a volatile chloride of a metal is 74.6. If the specific heat of the metal is 0.55, then the atomic mass of the metal is

Accepted Answer

Approximate atomic mass of metal $= \frac{6.4}{0.55} = 11.63$

Let the metal chloride be MCl_V. Then,

$2 \times 74.6 = 11.63 + V \times 35.5 \Rightarrow V \approx 4$

Again, $2 \times 74.6 = A + 4 \times 35.5 \Rightarrow A = 7.2$

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