Redox and Equivalent ConceptHard

Question

The vapour density of a volatile chloride of a metal is 74.6. If the specific heat of the metal is 0.55, then the atomic mass of the metal is

Options

A.7.2
B.7.46
C.11.63
D.10

Solution

Approximate atomic mass of metal $= \frac{6.4}{0.55} = 11.63$

Let the metal chloride be MClV. Then,

$2 \times 74.6 = 11.63 + V \times 35.5 \Rightarrow V \approx 4$

Again, $2 \times 74.6 = A + 4 \times 35.5 \Rightarrow A = 7.2$

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