Mole ConceptHard
Question
A volume of 60 ml of a mixture of nitrous oxide and nitric oxide was exploded with excess hydrogen. If 38 ml of N2 was formed, the volume of nitrous oxide in the original mixture is
Options
A.16 ml
B.44 ml
C.27 ml
D.33 ml
Solution
N2O + H2 → N2 + H2O
x mL x mL
$NO + H_{2} \rightarrow \frac{1}{2}N_{2} + H_{2}O $$$(60 - x)\text{ mL} \frac{1}{2}(60 - x)\text{ mL}$$
From question, $x + \frac{1}{2}(60 - x) = 38 \Rightarrow x = 16$
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