Mole ConceptHard
Question
How much NaNO3 must be weighed out to make 50 ml of an aqueous solution containing 70 mg of Na+ per mL ?
Options
A.12.394 g
B.1.29 g
C.10.934 g
D.12.934 g
Solution
Explanation : M. wt. of NaNO3 = 85
70 mg of Na+ are present in 1 mL
50 ml of solution contains 50 × 70 = 3500 mg = 3.5 g Na+ ion
23 g of Na+ are present in 85 g of NaNO3
3.5 g of Na+ are present in
× 3.5 = 12.934 g of NaNO3
70 mg of Na+ are present in 1 mL
50 ml of solution contains 50 × 70 = 3500 mg = 3.5 g Na+ ion
23 g of Na+ are present in 85 g of NaNO3
3.5 g of Na+ are present in
× 3.5 = 12.934 g of NaNO3Create a free account to view solution
View Solution FreeMore Mole Concept Questions
Assume that sodium atoms are spheres of radius 0.2 nm and that they are lined up side by side. How many miles, in length...The percentage of Fe(III) present in iron ore Fe0.93 O1.00 is (Fe = 56)...64 g of an organic compound has 24 g carbon and 8 g hydrogen and the rest is oxygen. The empirical formula of the compou...Assuming that 1,3,5-hexatriene has only pure double bonds and pure single bonds, how many grams of it contain one mole o...An amount of 2 moles of KClO3 is decomposed completely to produce O2 gas. How many moles of butene C4H8 can be burnt com...