Mole ConceptHard
Question
How much NaNO3 must be weighed out to make 50 ml of an aqueous solution containing 70 mg of Na+ per mL ?
Options
A.12.394 g
B.1.29 g
C.10.934 g
D.12.934 g
Solution
Explanation : M. wt. of NaNO3 = 85
70 mg of Na+ are present in 1 mL
50 ml of solution contains 50 × 70 = 3500 mg = 3.5 g Na+ ion
23 g of Na+ are present in 85 g of NaNO3
3.5 g of Na+ are present in
× 3.5 = 12.934 g of NaNO3
70 mg of Na+ are present in 1 mL
50 ml of solution contains 50 × 70 = 3500 mg = 3.5 g Na+ ion
23 g of Na+ are present in 85 g of NaNO3
3.5 g of Na+ are present in
× 3.5 = 12.934 g of NaNO3Create a free account to view solution
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