Mole ConceptHard
Question
When the hydrocarbon propane is burned in air, carbon dioxide and water are formed. If 0.15 mol of CO2 is produced, then how many drops of water will be formed, assuming one drop is 0.05 cm3 and contains
1.70 × 1021 water molecules?
Options
A.1.2 × 1023
B.4
C.53
D.70
Solution
$C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O$
0.15 mole 0.20 mol
∴ Number of water droplets =$= \frac{0.2 \times 6 \times 10^{23}}{1.7 \times 10^{21}} = 70.6 = 70$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
A volume of 100 ml of M–NaCl solution, 100 ml of 2 M–MgCl2 solution and 300 ml of 4 M–Mg(NO3)2 solution is mixed togethe...The enthalpy of vapour is 10 kcal/mole higher than liquid at 350 K and 2 atm. Under given conditions, the difference in ...A mixture of 254 g of iodine and 142 g of chlorine is made to react completely to give a mixture of ICl and ICl3. How ma...Mole fraction of the solute in a 1.00 molal aqueous solution is...‘n’ mol of N2 and 0.05 mol of Ar is enclosed in a vessel of capacity 6 L at 1 atm and 27°C. The value of ‘n’ is(R = 0.08...