Mole ConceptHard
Question
When the hydrocarbon propane is burned in air, carbon dioxide and water are formed. If 0.15 mol of CO2 is produced, then how many drops of water will be formed, assuming one drop is 0.05 cm3 and contains
1.70 × 1021 water molecules?
Options
A.1.2 × 1023
B.4
C.53
D.70
Solution
$C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O$
0.15 mole 0.20 mol
∴ Number of water droplets =$= \frac{0.2 \times 6 \times 10^{23}}{1.7 \times 10^{21}} = 70.6 = 70$
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