Mole ConceptMedium
Question
‘n’ mol of N2 and 0.05 mol of Ar is enclosed in a vessel of capacity 6 L at 1 atm and 27°C. The value of ‘n’ is
(R = 0.08 L atm mol−1 K–1)
Options
A.0.25
B.0.20
C.0.05
D.0.4
Solution
$(n + 0.05) = \frac{1 \times 6}{0.08 \times 300} \Rightarrow n = 0.20$
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