Mole ConceptMedium
Question
The enthalpy of vapour is 10 kcal/mole higher than liquid at 350 K and 2 atm. Under given conditions, the difference in internal energy of vapour and liquid will be -
Options
A.10700 cal.
B.-9300 cal.
C.9300 cal.
D.- 10700 cal.
Solution
H2O(l) → H2O(g)
ᐃH = ᐃU + ᐃngRT
10000 = → U + 1 × 2 × 250
⇒ ᐃU = 9300 ca
ᐃH = ᐃU + ᐃngRT
10000 = → U + 1 × 2 × 250
⇒ ᐃU = 9300 ca
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