Mole ConceptMedium
Question
How many grams of 90% pure Na2SO4 can be produced from 250 g of 95% pure NaCl?
Options
A.640.6 g
B.288.2 g
C.259.4 g
D.320.3 g
Solution
2NaCl → Na2SO4
2 × 58.5 g 142 g
$\therefore 250 \times \frac{95}{100}g \frac{142}{2 \times 58.5} \times (250 \times 0.95) = 288.248\text{ g}$
Hence, mass of 90 per cent pure Na2SO4 sample produced = 288.248 × (100/90) = 320.275 g.
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