Mole ConceptMediumBloom L3
Question
The density (in g mL-1) of a 3.60 M sulphuric acid solution that is 29% H2SO4 (Molar mass = 98 g mol-1) by mass will be
Options
A.1.64
B.1.88
C.1.22
D.1.45
Solution
Let the density of solution be ′d′
Molarity of solution given = 3.6
i.e. 1 litre of solution contains 3.6 moles of H2SO4
or 1 litre of solution contains 3.6 × 98 gms of H2SO4
Since, the solution is 29% by mass.
100 gm solution contains 29 gm H2SO4
mi solution contains 29 gm of H2SO4
1000 ml solution contains 3.6 × 98 gm of H2SO4
∴ 3.6 × 98 =
× 1000
d = 1.22
Hence, (3) is correct.
Molarity of solution given = 3.6
i.e. 1 litre of solution contains 3.6 moles of H2SO4
or 1 litre of solution contains 3.6 × 98 gms of H2SO4
Since, the solution is 29% by mass.
100 gm solution contains 29 gm H2SO4
mi solution contains 29 gm of H2SO41000 ml solution contains 3.6 × 98 gm of H2SO4
∴ 3.6 × 98 =
× 1000 d = 1.22
Hence, (3) is correct.
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