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Question

When 20 g Fe2O3 is reacted with 50 g of HCl, FeCl3 and H2O are formed. The amount of unreacted HCl is

(Fe = 56)

Options

A.27.375 g
B.22.625 g
C.30 g
D.4.75 g

Solution

Fe2O3 + 6HCl → 2FeCl3 + 3H2O

160 g 6 × 36.5 g

$\therefore 20\text{ g} \frac{6 \times 36.5}{160} \times 20 = 27.375\text{ g}$

Hence, the mass of unreacted HCl = 50 − 27.375 = 22.625 g

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