Mole ConceptHard

Question

$A + 2\text{ }B \longrightarrow {AB}_{2}$; 36.0 g of 'A' (Molar mass: $60\text{ }g{\text{ }mol}^{- 1}$ ) and 56.0 g of ' B ' (Molar mass: $80\text{ }g{\text{ }mol}^{- 1}$ ) are allowed to react. Which of the following statements are correct?

(A) ' A ' is the limting reagent
(B) 
77.0 g of ${AB}_{2}$ is formed

(C) Molar mass of $AB_{2}$ is $140\text{ }g{\text{ }mol}^{- 1}$

(D) 15.0 g of A is left unreacted after the completion of reaction.

Choose the correct answer from the options given below:

Options

A.C and D only
B.A and C only
C.B and D only
D.

A and B only

Solution

$\ A + 2\text{ }B \longrightarrow {AB}_{2}$

Mole $\frac{36}{60}\ \frac{56}{80}$

0.6 mole 0.7 mole

0.25 mole 0.35 mole

A) Molecular wt. of ${AB}_{2}$ is

$$60 + 2 \times 80 = 220\text{ }g/mol $$B) LR is AB .

C) Wt. of A remaining $= 0.25 \times 60 = 15\text{ }g$

D) wt. of ${AB}_{2}$ formed $= 0.35 \times 220 = 77gm$.

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