Mole ConceptMedium
Question
A quantity of 0.25 g of a substance when vaporized displaced 50 cm3 of air at 0o C and 1 atm. The gram molecular mass of the substance will be
Options
A.50 g
B.100 g
C.112 g
D.127.5 g
Solution
$M = \frac{0.25}{50} \times 22400 = 112\text{g/mol}$
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