Mole ConceptHard
Question
25 mL of an aqueous solution of KCl was found to require 20 mL of 1 M AgNO3 solution when titrated using a K2CrO4 as indicator. The depression in freezing point of KCl solution with 100% ionization will be:
[Kf = 2.0o mol-1 Kg and molarity = molality]
[Kf = 2.0o mol-1 Kg and molarity = molality]
Options
A.5.0o
B.3.2o
C.1.6o
D.0.8o
Solution
25 × M(KCl) = 20 × 1 M(AgNO3)
∴ M(KCl) = 0.8
ᐃTf = M′fi
= 0.8 × 2 × 2
∴ M(KCl) = 0.8
ᐃTf = M′fi
= 0.8 × 2 × 2
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