Mole ConceptHard

Question

An amount of 1.0 × 10–3 moles of Ag+ and 1.0 × 10–3 moles of CrO4 2− reacts together to form solid Ag2CrO4. What is the amount of Ag2CrO4 formed? (Ag = 108, Cr = 52)

Options

A.0.332 g
B.0.166 g
C.332 g
D.166 g

Solution

$2Ag^{+} + CrO_{4}^{2 -} \rightarrow Ag_{2}CrO_{4}$

$10^{- 3}\text{mole}\left( \text{LR} \right) 10^{- 3}\text{ mole} \frac{332}{2} \times 10^{3} = 0.166\text{ g}$

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