Question
Given below are two statements:
Statement I: Among $\left\lbrack Cu\left( {NH}_{3} \right)^{2 +},\left\lbrack Ni(en)_{3} \right) \right\rbrack^{2 +}$, $\left\lbrack Ni\left( {NH}_{3} \right)_{6} \right\rbrack^{2 +}$ and $\left\lbrack Mn\left( H_{2}O \right)_{6} \right\rbrack^{2 +},\left\lbrack Mn\left( H_{2}O \right)_{6} \right\rbrack^{2 +}$, has the maximum number of unpaired electrons.
Statement II: The number of pairs among $\left\{ \left\lbrack {NiCl}_{4} \right\rbrack^{2 -},\left\lbrack Ni(CO)_{4} \right\rbrack \right\},\left\{ \left\lbrack {NiCl}_{4} \right\rbrack^{2 -},\left\lbrack Ni(CN)_{4} \right\rbrack^{2 -} \right.\ $ and $\left\{ \left\lbrack Ni(CO)_{4} \right\rbrack,\ \left\lbrack Ni(CN)_{4} \right\rbrack^{2 -} \right\}\ $ that contain only diamagnetic species is two.
In the light of the above statements, choose the correct answer from the options given below:
Options
Solution
$\left\lbrack Cu\left( {NH}_{3} \right)_{4} \right\rbrack^{2 +} \Rightarrow d^{9},{dsp}^{2}$ one unpaired electron
$\left\lbrack Ni(en)_{3} \right\rbrack^{2 +} \Rightarrow d^{8},{sp}^{3}{\text{ }d}^{2}$ two unpaired electrons
$\left\lbrack Ni\left( {NH}_{3} \right)_{6} \right\rbrack^{2 +} \Rightarrow d^{8},{sp}^{3}{\text{ }d}^{2}$ two unpaired electrons
$\left\lbrack Mn\left( H_{2}O \right)_{6} \right\rbrack^{2 +} \Rightarrow d^{5},{sp}^{3}{\text{ }d}^{2}$ five unpaired electrons
$\left\lbrack Ni(CO)_{4} \right\rbrack$ (diamagnetic)
$\left\lbrack {NiCl}_{4} \right\rbrack^{- 2}$ (paramagnetic)
$\left\lbrack Ni(CN)_{4} \right\rbrack^{- 2}$ (diamagnetic)
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