Atomic StructureEasy
Question
If uncertainty in position and momentum of a particle is numerically equal, then the minimum uncertainty in speed of the particle should be
Options
A.$\sqrt{\frac{h}{2\pi}}$
B.$\frac{1}{2m}\sqrt{\frac{h}{\pi}}$
C.$\sqrt{\frac{h}{\pi}}$
D.$\frac{1}{m}\sqrt{\frac{h}{\pi}}$
Solution
If the numerical values of Δx and Δp is x, then $x \geq \sqrt{\frac{h}{4\pi}}$
$\therefore\Delta{v\frac{1}{m}\sqrt{\frac{h}{4\pi}}}_{\min}$
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