Atomic StructureEasy
Question
Wavelength of photon having energy 1 eV would be
Options
A.1.24 × 10–4 m
B.1.24 × 10–6 m
C.1.24 × 10–5 m
D.1.24 × 104 m
Solution
$\lambda = \frac{12400}{E}\overset{o}{A} - eV = \frac{12400}{1} = 12400\overset{o}{A} = 12400 \times 10^{- 10} = 1.24 \times 10^{- 6}\text{ m}$
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