Atomic StructureHard

Question

An electron is revolving around the nucleus of He+ ion with a speed of 2.188 × 106 m/s. The potential energy of the electron is

Options

A.–13.6 eV
B.–6.8 eV
C.–27.2 eV
D.Zero

Solution

$V_{n,z} = 2.188 \times 10^{6}\frac{z}{n}\text{ m/s}$

$\Rightarrow 2.188 \times 10^{6} = 2.188 \times 10^{6} \times \frac{2}{n} \Rightarrow n = 2 $$$\text{Now, P.E. = } - 27.2 \times \frac{z^{2}}{n^{2}} = - 27.2 \times \frac{2^{2}}{2^{2}} = - 27.2\text{ eV}$$

Create a free account to view solution

View Solution Free
Topic: Atomic Structure·Practice all Atomic Structure questions

More Atomic Structure Questions

There are two samples of H and He atom. Both are in some excited state. In hydrogen atom total number of lines observed ...The excitation energy of an electron from second orbit to third orbit of a hydrogen-like atom or ion with +Ze nuclear ch...No. of visible lines when an electron returns from 5th orbit to ground state in H spectrum -...What is the most probable distance of a 1s electron in a He+ ion. The wave function for 1s orbital is given by $\Psi = \...A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu....