Atomic StructureEasy

Question

An electron is revolving around the nucleus of He+ ion with a speed of 2.188 × 106 m/s. The potential energy of the electron is

Options

A.–13.6 eV
B.–6.8 eV
C.–27.2 eV
D.Zero

Solution

$V_{n,z} = 2.188 \times 10^{6}\frac{z}{n}\text{ m/s}$

$\Rightarrow 2.188 \times 10^{6} = 2.188 \times 10^{6} \times \frac{2}{n} \Rightarrow n = 2 $$$\text{Now, P.E. = } - 27.2 \times \frac{z^{2}}{n^{2}} = - 27.2 \times \frac{2^{2}}{2^{2}} = - 27.2\text{ eV}$$

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