Atomic StructureMedium
Question
The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 × 10-27 ms-1 respectively then the mass of the particle is : (h = 6.625 × 10-34Js)
Options
A.200 g
B.300 g
C.100 g
D.1000 g
Solution
ᐃx = 0.1 × 10-9 m.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
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