Atomic StructureHard
Question
The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 × 10-27 ms-1 respectively then the mass of the particle is : (h = 6.625 × 10-34Js)
Options
A.200 g
B.300 g
C.100 g
D.1000 g
Solution
ᐃx = 0.1 × 10-9 m.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The types and number of orbitals belonging from the fifth orbit are, respectively,...When the value of azimuthal quantum number is 3, the maximum and minimum values of spin multiplicity are...In two hydrogen atoms A and B, the electrons are revolving around the nucleus in circular orbits of radius r and 4r, res...Last line of Lyman series for H-atom has wavelength λ1, 2nd line of Balmer series has wavelength λ2 Å then...A certain laser transition emits 6.0 × 1015 quanta per second per square metre of λ = 662.6 nm. What is the power output...