Atomic StructureHard
Question
The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 × 10-27 ms-1 respectively then the mass of the particle is : (h = 6.625 × 10-34Js)
Options
A.200 g
B.300 g
C.100 g
D.1000 g
Solution
ᐃx = 0.1 × 10-9 m.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
DV = 5.27 × 10-27 ms-1.
ᐃV = 5.27 × 10-27 ms-1.
∴ ᐃx × mᐃV =
∴ 0.1 × 10-9 × m × 5.27 × 10-27 = 0.527 × 10-34.
∴ m = 0.1 kg. = 100 gm.
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Photon having wavelength 310 nm is used to break the bond of A2 molecule having bond energy 288 kJ mol-1 then % of energ...In which of the following orbital, electron will be closer to the nucleus?...If an electron in H-atom jumps from one orbit to other, its angular momentum doubles. The distance of electron from nucl...The wave function of 1s orbital of H-atom is $\Psi = \frac{1}{\sqrt{\pi}}\left( \frac{1}{a_{0}} \right)^{3/2}e^{- r/a_{0...The orbital angular momentum of an electron is 2s orbital is...