Atomic StructureHard
Question
What should be the increase in kinetic energy of electron in order to decrease its de Broglie wavelength from 100 nm to 50 nm?
Options
A.0.451 keV
B.4.51 × 10−4 eV
C.4.51 × 10−3 eV
D.0.0451 eV
Solution
$\lambda = \frac{h}{\sqrt{2mE}} \Rightarrow \Delta E = \frac{h^{2}}{2m}\left( \frac{1}{\lambda_{2}^{2}} - \frac{1}{\lambda_{1}^{2}} \right)$
$= \frac{\left( 6.626 \times 10^{- 34} \right)^{2}}{2 \times 9 \times 10^{- 31}}\left( \frac{1}{\left( 50 \times 10^{- 9} \right)^{2}} - \frac{1}{\left( 100 \times 10^{- 9} \right)^{2}} \right) $$$= 7.24 \times 10^{- 23}\text{ J = 4.5} \times \text{1}\text{0}^{- 4}\text{ eV}$$
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