Atomic StructureEasy
Question
The ratio of potential energy of electron in the third orbit of Li2+ ion to the kinetic energy of electron in the fourth orbit of He+ ion should be
Options
A.8: 1
B.–8: 1
C.–16: 1
D.1: 1
Solution
$\frac{(P.E.)_{3,Li^{2 +}}}{(K.E.)_{4,He^{+}}} = \frac{- 27.2 \times \frac{3^{2}}{2^{2}}}{13.6 \times \frac{2^{2}}{4^{2}}} = - \frac{8}{1}$
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