Atomic StructureHard
Question
The ratio of potential energy of electron in the third orbit of Li2+ ion to the kinetic energy of electron in the fourth orbit of He+ ion should be
Options
A.8: 1
B.–8: 1
C.–16: 1
D.1: 1
Solution
$\frac{(P.E.)_{3,Li^{2 +}}}{(K.E.)_{4,He^{+}}} = \frac{- 27.2 \times \frac{3^{2}}{2^{2}}}{13.6 \times \frac{2^{2}}{4^{2}}} = - \frac{8}{1}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The respective values of orbital angular momentum of an electron in 1s, 2s, 3d and 3p-orbitals are:-...The following electronic transitions occur when Lithium atoms are sprayed into a hot flame;Which of these transition wou...S1 : Bohr model is applicable for Be2+ ion.S2 : Total energy coming out of any light source is integral multiple of ener...When the reaction, 2NO2(g) ⇋ N2O4(g) reaches equilibrium at 298 K. The partial of NO2 and N2O4 are 0.2 KPa and 0.4...Which of the following particle have non-zero e/m ratio?...