Atomic StructureEasy
Question
The I.P. of an atom is 36 eV. What is the value of second excitation potential :-
Options
A.5 eV
B.12 eV
C.32 eV
D.27 eV
Solution
Second excitation potential means energy required to move from 1st to 3rd orbit
E1 = - 36 eV
E3 =
= - 4 eV
E3 - E1 = - 4 - (- 36 eV) = 32 eV
E1 = - 36 eV
E3 =
= - 4 eVE3 - E1 = - 4 - (- 36 eV) = 32 eV
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