Atomic StructureEasy
Question
The ratio of energies of first excited state of He+ ion and ground state of H–atom is
Options
A.1: 1
B.4: 1
C.1: 4
D.16: 1
Solution
$E_{n,z} = - 13.6 \times \frac{z^{2}}{n^{2}}eV$
$\therefore\frac{E_{2,He^{+}}}{E_{1,H}} = \frac{- 13.6 \times \frac{2^{2}}{2^{2}}}{- 13.6 \times \frac{1^{2}}{1^{2}}} = \frac{1}{1}$
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