Atomic StructureHard
Question
Magnetic moment of Xn+ (Z = 26) is 
B.M. Hence number of unpaired electrons and value of n respectively are ;
B.M. Hence number of unpaired electrons and value of n respectively are ;Options
A.Magnetic moment of Xn+ (Z = 26) is B.M. Hence number of unpaired electrons and value of n respectively are ;
B.M. Hence number of unpaired electrons and value of n respectively are ;B.2, 4
C.3, 1
D.0, 2
Solution
Magnetic moment = 
B.M
No. of unpaired electron = 4.
X26 : 1s2 2s22p63s23p63d64s2.
To get 4 unpaired electrons, outermost configuration will be 3d6.
∴ No. of electrons lost = 2 (from 4s2).
∴ n = 2.
B.MNo. of unpaired electron = 4.
X26 : 1s2 2s22p63s23p63d64s2.
To get 4 unpaired electrons, outermost configuration will be 3d6.
∴ No. of electrons lost = 2 (from 4s2).
∴ n = 2.
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