When electron jumps from the fourth orbit to the second orbit in He+ ion, the radiation emitted out

Question

When electron jumps from the fourth orbit to the second orbit in He+ ion, the radiation emitted out will fall in

Accepted Answer

$\frac{1}{\lambda} = Rz^{2}\left( \frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \right) = R \times 2^{2}\left( \frac{1}{2^{2}} - \frac{1}{4^{2}} \right)$

$\Rightarrow \lambda = 1223\overset{o}{A}$

∴ UV region.

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