Atomic StructureEasy
Question
The e/m ratio of a particle of charge 2 unit and mass 4 amu is
Options
A.4.8 × 107 C/kg
B.0.5 C/kg
C.4.8 × 104 C/kg
D.8 × 10–20 C/kg
Solution
$\frac{e}{m} = \frac{2 \times 1.602 \times 10^{- 19}C}{4 \times 1.67 \times 10^{- 27}\text{ kg}} \simeq 4.8 \times 10^{7}\text{C/Kg}$
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