Atomic StructureHard
Question
Let υ1 be the frequency of the series limit of the Lyman series, υ2 be the frequency of the first line of the Lyman series, and υ3 be the frequency of the series limit of the Balmer series -
Options
A.υ1 - υ2 = υ3
B.υ2 - υ1 = υ3
C.υ3 = 1/2 (υ1 - υ3)
D.υ1 + υ2 = υ3
Solution
v = RC Z2
.
v1 = RC Z2
= RC Z2 , v2 = RC Z2
RC Z2.
v3 = RC Z2
RC Z2. ∴ υ1 - υ2 = υ3.
v1 = RC Z2
v3 = RC Z2
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
When accelerated electrons are directed against an anticathode in an X-ray tube, the radiation obtained has a continuous...The de Broglie wavelength of a vehicle moving with velocity v is λ. Its load is changed so that the velocity as well as ...The corrent ground state electronic configuration of chromium atom is :...Magnetic moment of Xn+ (Z = 26) is B.M. Hence number of unpaired electrons and value of n respectively are ;...From the α-particle scattering experiment, Rutherford concluded that...