Atomic StructureMedium
Question
Let υ1 be the frequency of the series limit of the Lyman series, υ2 be the frequency of the first line of the Lyman series, and υ3 be the frequency of the series limit of the Balmer series -
Options
A.υ1 - υ2 = υ3
B.υ2 - υ1 = υ3
C.υ3 = 1/2 (υ1 - υ3)
D.υ1 + υ2 = υ3
Solution
v = RC Z2 
.
v1 = RC Z2
= RC Z2 , v2 = RC Z2 
RC Z2.
v3 = RC Z2
RC Z2. ∴ υ1 - υ2 = υ3.
.v1 = RC Z2
= RC Z2 , v2 = RC Z2 RC Z2.v3 = RC Z2
RC Z2. ∴ υ1 - υ2 = υ3.Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Maximum number of electrons in a subshell with l = 3 and n = 4 is...The binding energy for the third electron in the ground state of Li-atom should be...Electronic configuration of an element is 1s2, 2s1, 2p2. It is...Which of the following information is true?...Consider the ground state of Cr atom (Z = 24). The number of electrons with the azimuthal quantum numbers I = 1 and 2 ar...