Atomic StructureHard
Question
Let υ1 be the frequency of the series limit of the Lyman series, υ2 be the frequency of the first line of the Lyman series, and υ3 be the frequency of the series limit of the Balmer series -
Options
A.υ1 - υ2 = υ3
B.υ2 - υ1 = υ3
C.υ3 = 1/2 (υ1 - υ3)
D.υ1 + υ2 = υ3
Solution
v = RC Z2
.
v1 = RC Z2
= RC Z2 , v2 = RC Z2
RC Z2.
v3 = RC Z2
RC Z2. ∴ υ1 - υ2 = υ3.
v1 = RC Z2
v3 = RC Z2
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Rutherford′s experiment on scattering of α- particles showed for the first time that the atom has...The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 × 10-27 ms-1 respectively then the mas...The number of nodal planes in a Px orbotal is :...What is likely to be orbit number for a circular orbit of diameter 20 nm of the hydrogen atom if we assume Bohr orbit to...Solubility product of silver bromide is 5.0 × 10-13. The quantity of potassium bromide (molar mass taken as 120 g o...