An antiproton has the mass of a proton but a charge of –e. If a proton and an antiproton orbited eac

Question

An antiproton has the mass of a proton but a charge of –e. If a proton and an antiproton orbited each other, then how far apart would they be in ground state of such a system? Mass of a proton is 1836 times the mass of an electron.

Accepted Answer

$u = \frac{m_{1}m_{2}}{m_{1} + m_{2}} = \frac{m_{p}.m_{p}}{m_{p} + m_{p}} = \frac{m_{p}}{2} = \frac{1836 	imes m_{e}}{2}$$	herefore r = \frac{0.529}{918}\overset{o}{A} = 0.058	ext{ pm}$

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