Atomic StructureHard
Question
The force of attraction on electron by the nucleus is directly proportional to
Options
A.$\frac{n^{3}}{Z^{4}}$
B.$\frac{Z^{3}}{n^{4}}$
C.$\frac{n^{4}}{Z^{2}}$
D.$\frac{Z^{2}}{n^{4}}$
Solution
$F = \frac{mv^{2}}{r} \propto \frac{\left( \frac{z}{n} \right)^{2}}{\left( \frac{n^{2}}{z} \right)} = \frac{z^{3}}{n^{4}}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
In an oil drop experiment, the following charges (in arbitrary units) were found on a series of oil droplets 4.5 × 10−18...A compound of Xe and F is found to have 53.5% Xe. What is the oxidation state of Xe in this compound ? (atomic mass of X...The momentum of a photon of wavelength 6626 nm will be...The energy of first (lowest) Balmer line of H atom is x J . The energy (in J) of second Balmer line of H atom is :...dz2 - orbital has :...