Atomic StructureHard
Question
At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light source containing Kr86 atoms. What is the corresponding photon energy of this radiation?
Options
A.3.28 × 10–19 J/quanta
B.1.2 × 10–31 J/quanta
C.1.09 × 10–27 J/quanta
D.2.048 J/quanta
Solution
$E = n.hc\bar{\upsilon} = 1 \times 6.626 \times 10^{- 34} \times 3 \times 10^{8} \times 1650763.73 = 3.28 \times 10^{- 19}\text{ J/quanta}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water. 0.2 g of the metal oxide...Which of the following compounds, conjugate base is stablized by d-orbital resonance -...The angular momentum of electron in an excited H atom is . The P.E. of electron will be :...If the radius of first orbit of H–atom is x Å, then the radius of the second orbit of Li2+ ion will be...Uncertainty in position is twice the uncertainty in momentum. Uncertainty in velocity is :...