Atomic StructureHard
Question
At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light source containing Kr86 atoms. What is the corresponding photon energy of this radiation?
Options
A.3.28 × 10–19 J/quanta
B.1.2 × 10–31 J/quanta
C.1.09 × 10–27 J/quanta
D.2.048 J/quanta
Solution
$E = n.hc\bar{\upsilon} = 1 \times 6.626 \times 10^{- 34} \times 3 \times 10^{8} \times 1650763.73 = 3.28 \times 10^{- 19}\text{ J/quanta}$
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
Which of the following statements is/are correct?In the reaction xCu3P + y Cr2O72- Cu2+ + H3PO4 + Cr3+...According to Bohr′s theory, the angular momentum of an electron in 5th orbit is...The uncertainty in the momentum of an electron is 1.0 × 10-5 kg m s-1. The uncertainty in its position will be: (h ...A bulb is rated at 150 watts, converting $8\%$ energy into light. If energy of one photon is $4.42 \times 10^{- 19}\text...The ratio of circumference of third and second orbits of He+ ion is...