Atomic StructureHard

Question

At one time the meter was defined as 1650763.73 wavelength of the orange light emitted by a light source containing Kr86 atoms. What is the corresponding photon energy of this radiation?

Options

A.3.28 × 10–19 J/quanta
B.1.2 × 10–31 J/quanta
C.1.09 × 10–27 J/quanta
D.2.048 J/quanta

Solution

$E = n.hc\bar{\upsilon} = 1 \times 6.626 \times 10^{- 34} \times 3 \times 10^{8} \times 1650763.73 = 3.28 \times 10^{- 19}\text{ J/quanta}$

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