Atomic StructureEasy
Question
The distance of closest approach of an α-particle fired towards a nucleus with momentum ‘P’ is r. What will be the distance of closest approach when the momentum of the α-particle is 2P?
Options
A.2r
B.4r
C.r/2
D.r/4
Solution
$r = K.\frac{q_{1}q_{2}}{\left( P^{2}/2m \right)} \Rightarrow r \propto \frac{1}{P^{2}}$
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