Atomic StructureHard
Question
In Balmer series of lines of hydrogen spectrum, the first line from the red end corresponds to which one of the following inter-orbit jumps of the electron for Bohr orbits in an atom of hydrogen ?
Options
A.5 → 2
B.4 → 1
C.2 → 5
D.3 → 2
Solution
1st line from red end in Balmer series.
⇒ Line of minimum energy in Balmer series.
∴ Transition = (3 → 2).
⇒ Line of minimum energy in Balmer series.
∴ Transition = (3 → 2).
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
A proton and an a-particle are accelerated through the same potential difference from rest. Then the ratio of their de B...The orbital with zero orbital angular momentum is-...If n and l are respectively the principal and azimuthal quantum numbers, then the expression for calculating the total n...In an experiment, 4g of M2Ox oxide was reduced to 2.8 g of the metal. If the atomic mass of the metal is 56 g mol-1. The...If electron is present in n1 orbit of hydrogen atom and n2 orbit of He+ ions then which of the following relation is cor...