Atomic StructureHard
Question
The ionization energy of H-atoms is 13.6 eV. The ionization energy of deuterium atom should be
Options
A.exactly 13.6 eV.
B.slightly less than 13.6 eV.
C.slightly greater than 13.6 eV.
D.27.2 eV.
Solution
Reduced mass effect:
$\left( \text{I.E.} \right)' = \left( \text{I.E.} \right).\frac{1}{\left( 1 + \frac{m_{e}}{m_{n}} \right)}$
On increasing the nuclear mass, ionisation energy increases.
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