Mole ConceptHard

Question

When 0.03 L of a mixture of hydrogen and oxygen was exploded, 0.003 L of oxygen remained. The initial mixture contains (by volume)

Options

A.60% O2
B.40% O2
C.50% O2
D.30% O2

Solution

2H2 + O2 → 2H2O

2V vol V vol

From question, 2V + V + 0.003 = 0.03

⇒ V = 0.009

∴ Percentage of oxygen $= \frac{0.009 + 0.003}{0.03} \times 100 = 40\%$

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