Mole ConceptHard
Question
If the yield of chloroform obtainable from acetone and bleaching powder is 75%, then what mass of acetone is required for producing 30 g of chloroform?
Options
A.40 g
B.19.4 g
C.10.92 g
D.14.56 g
Solution
$2CH_{3}COCH_{3} + 6Ca(OCl)Cl\overset{\quad 75\%\quad}{\rightarrow}2CHCl_{3} + \left( CH_{3}COO \right)_{2}Ca + 3CaCl_{2} + 2Ca(OH)_{2}$
2 × 58 g 2 × 119.5 g
∴ For 30 g CHCl3, mass of CH3COCH3 needed = $\frac{2 \times 58}{2 \times 119.5} \times 30 \times \frac{100}{75} = 19.4\text{ g}$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
What is the mole fraction of water in 10% by weight (w/w) of aqueous urea solution ?[Given : Molar mass of H, O, C and N...A sample of crystalline soda A with a mass of 1.287 g was allowed to react with an excess of hydrochloric acid and 100.8...Which of the following is the incorrect conclusion regarding the following reaction?2 H2(g) + O2(g) → 2 H2O(l)...A quantity of 0.25 g of a substance when vaporized displaced 50 cm3 of air at 0o C and 1 atm. The gram molecular mass of...According to the collision theory, most molecular collisions do not lead to reaction. Which of the following is/are nece...