Mole ConceptHard

Question

A quantity of 2.0 g of a triatomic gaseous element was found to occupy a volume of 448 ml at 76 cm of Hg and 273 K. The mass of its each atom is

Options

A.100 amu
B.5.53 × 10–23 g
C.33.3 g
D.5.53 amu

Solution

$\frac{2}{3A} = \frac{1 \times (448/1000)}{0.0821 \times 273} \Rightarrow \text{Atomic mass, A=}\frac{100}{3}$

Hence, mass of each atom = $\frac{100}{3} \times 1.66 \times 10^{- 24} = 5.53 \times 10^{- 23}g$

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