Mole ConceptHard

Question

A mixture of NaI and NaCl on reaction with H2SO4 gave Na2SO4 equal to the weight of original mixture taken. The percentage of NaI in the mixture is (I = 127)

Options

A.82.86
B.26.38
C.62.38
D.28.86

Solution

2NaI → Na2SO4

2 × 150 g 142 g

$\therefore xg \frac{142}{300} \times x\text{ g}$

2NaCl → Na2SO4

2 × 58.5 g 142 g

$\therefore(100 - x)g \frac{142}{117} \times (100 - x)g$

From the question, $\frac{142}{300} \times x + \frac{142}{117} \times (100 - x) = 100$

Hence, the percentage of NaI in the mixture = 28.86%

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